2013 AMC 8 第 10 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

10.

180180594594 的最小公倍数与 180180594594 的最大公因数之比是多少?

What is the ratio of the least common multiple of 180180 and 594594 to the greatest common factor of 180180 and 594?594?

110110

165165

330330

625625

660660

答案:C
知识点:质因数分解最大公约数最小公倍数
难度评级:1240
视频讲解:
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文字解答:

将两个数质因数分解: 180=22325,180=2^2\cdot3^2\cdot5, 594=23311.594=2\cdot3^3\cdot11.

最大公因数取较小的幂,所以为 232=182\cdot3^2=18。 最小公倍数取较大的幂,所以为 所求比值为 594018=330\dfrac{5940}{18}=3302233511=5940.2^2\cdot3^3\cdot5\cdot11=5940.

所以正确答案是 C

Prime-factorize the two numbers: 180=22325,180=2^2\cdot3^2\cdot5, 594=23311.594=2\cdot3^3\cdot11.

The greatest common factor uses the smaller powers, so it is 232=182\cdot3^2=18. The least common multiple uses the larger powers, so it is 2233511=5940.2^2\cdot3^3\cdot5\cdot11=5940. Therefore the desired ratio is 594018=330\dfrac{5940}{18}=330.

Thus, C is the correct answer.

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