2012 AMC 8 第 19 题

先试着解答 2012 AMC 8 第 19 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2012 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

19.

一个罐子里有红色、绿色和蓝色弹珠。除了 66 个以外全是红弹珠,除了 88 个以外全是绿弹珠,除了 44 个以外全是蓝弹珠。罐子里有多少个弹珠?
In a jar of red, green, and blue marbles, all but 66 are red marbles, all but 88 are green, and all but 44 are blue. How many marbles are in the jar?
66
88
99
1010
1818
答案:C
知识点:方程组
小提示:
将每个“除了……以外全是”语句翻译成另外两种颜色的和。
Translate each “all but” statement into a sum of two colors.
大提示:
把三个方程相加时,每个弹珠被数了两次。
Adding the three equations counts every marble twice.
视频讲解:
解答视频缩略图
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文字解答:
设红、绿、蓝弹珠数分别为 r,g,br,g,b。由题意可知 r+g+b−r=6,r+g+b -r=6\text{,}r+g+b−g=8,r+g+b-g = 8\text{,}r+g+b−b=4。 r+g+b-b = 4\text{。}把这些方程相加,得到 3(r+g+b)−(r+g+b)=183(r+g+b) -(r+g+b) = 18。因此 2(r+g+b)=182(r+g+b) = 18,所以 r+g+b=9r+g+b = 9。也就是说,弹珠总数为 99。
所以正确答案是 C。
Let r,g,br,g,b be the number of red marbles, green marbles, and blue marbles respectively. We then know r+g+b−r=6,r+g+b -r=6,r+g+b−g=8,r+g+b-g = 8,r+g+b−b=4 r+g+b-b = 4 by the statements given. Adding these equations yields 3(r+g+b)−(r+g+b)=18.3(r+g+b) -(r+g+b) = 18. This would mean 2(r+g+b)=18,2(r+g+b) = 18, so r+g+b=9.r+g+b = 9. Therefore, the sum of all of the marbles is 9.9.
Thus, the answer is C .
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