2012 AMC 8 第 14 题

先试着解答 2012 AMC 8 第 14 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2012 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

14.

在中学橄榄球联盟 BIG N 中,每支球队与其他每支球队恰好比赛一次。如果 20122012 赛季共进行了 2121 场联盟比赛,那么 BIG N 联盟有多少支球队?
In the BIG N, a middle school football conference, each team plays every other team exactly once. If a total of 2121 conference games were played during the 20122012 season, how many teams were members of the BIG N conference?
66
77
88
99
1010
答案:B
知识点:组合三角形数
小提示:
列出每增加一支球队会新增多少场比赛。
List how many games are added when each new team joins.
大提示:
nn 支球队时,比赛场数为 n(n−1)2\frac{n(n-1)}{2}。
With nn teams, the number of games is n(n−1)2\frac{n(n-1)}{2}.
视频讲解:
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文字解答:
若有 NN 支球队,每支球队要与 N−1N-1 支球队比赛。不过,每场比赛涉及 22 支球队,所以把 NN 与 N−1N-1 相乘会把每场比赛数两次。因此 N(N−1)=42N(N-1) = 42。这给出 N2−N+0.25=42.25N^2 -N +0.25 = 42.25 从而 (N−0.5)2=6.52,(N-0.5)^2 = 6.5^2\text{,}于是 N−0.5=6.5N-0.5 = 6.5N=7 N = 7
所以正确答案是 B。
Each of the NN teams plays N−1N-1 games. However, 22 teams play each game, so multiplying NN and N−1N-1 would be twice the number of games. Therefore, we know N(N−1)=42.N(N-1) = 42. This leads to N2−N+0.25=42.25N^2 -N +0.25 = 42.25 which implies (N−0.5)2=6.52.(N-0.5)^2 = 6.5^2. In turn, this suggests: N−0.5=6.5N-0.5 = 6.5N=7 N = 7
Thus, the answer is B .
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