2008 AMC 8 第 13 题

先试着解答 2008 AMC 8 第 13 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2008 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

13.

哈曼先生想知道他要邮寄的三个箱子的总重量,单位为磅。不过唯一可用的秤在重量小于 100100 磅或大于 150150 磅时不准确。于是他把箱子按所有可能的两两组合称重,结果是 122122、125125 和 127127 磅。这三个箱子的总重量是多少磅?
Mr. Harman needs to know the combined weight in pounds of three boxes he wants to mail. However, the only available scale is not accurate for weights less than 100100 pounds or more than 150150 pounds. So the boxes are weighed in pairs in every possible way. The results are 122,122, 125125 and 127127 pounds. What is the combined weight in pounds of the three boxes?
 160\ 160
 170\ 170
 187\ 187
 195\ 195
 354\ 354
答案:C
知识点:方程组
小提示:
三个两箱重量之和中,每个箱子都恰好出现两次
Each box appears in exactly two of the three pair weights.
大提示:
把三个两箱重量相加,再除以 22
Add the three pair weights, then divide by 2.2.
解答:
设三个箱子的重量为 aa、bb、cc。已知 {a+b=122a+c=125b+c=127。\begin{cases}a+b = 122\\a+c = 125\\b+c = 127\end{cases}\text{。}把这些式子相加得到 2(a+b+c)=2(a+b+c) = 122+125+127=374。 122+125+127=374\text{。}所以 a+b+c=187。a+b+c = 187\text{。}
所以正确答案是 C。
Let the weights be a,a, b,b, c.c. We know {a+b=122a+c=125b+c=127.\begin{cases}a+b = 122\\a+c = 125\\b+c = 127.\end{cases} Adding all of this yields 2(a+b+c)=2(a+b+c) =122+125+127=374. 122+125+127=374. This makes a+b+c=187.a+b+c = 187.
Thus, the answer is C .
LIVE by Po-Shen Loh
LIVE项目

LIVE直播课程

Self-Paced录播课程

启明星Star计划

奖学金项目

关于我们

罗博深是谁?

邮件联系

订阅英文简报

加入我们

申请明星导师

For a more Thought Full world.

© 2026 Expii, Inc.