1994 AMC 8 第 15 题

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15.

如果这条路径按相同规律继续,那么从点 425425 到点 427427 的箭头序列是哪一个?

If this path is to continue in the same pattern, then which sequence of arrows goes from point 425425 to point 427?427?

答案:A
知识点:模运算找规律
难度评级:910
解答:

这个模式每 44 个点重复一次,所以从某点出发的箭头只取决于它除以 44 的余数。

因为 425=4(106)+1425 = 4(106) + 1,且 427=4(106)+3427 = 4(106) + 3,所以从 425425427427 的路径与从点 11 到点 33 相同:从 11 向上到 22,再向右到 33

所以正确答案是 A

The pattern repeats every 44 points, so the arrows leaving a point depend only on its remainder upon division by 4.4.

Because 425=4(106)+1425 = 4(106) + 1 and 427=4(106)+3,427 = 4(106) + 3, the path from 425425 to 427427 looks just like the path from point 11 to point 33: from 11 it goes up to 2,2, then right to 3.3.

Thus, the correct answer is A .

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