1993 AMC 8 第 13 题

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13.

单词 HELP 用宽 11 单位的笔画在一个 551515 的长方形标牌上画成阴影区域。每个字母宽 33 单位,字母之间间隔 11 单位,如图所示。标牌未涂色部分的面积是多少平方单位?

The word "HELP" in block letters is painted as a shaded region with strokes 11 unit wide on a 55 by 1515 rectangular sign. Each letter is 33 units wide with a 11-unit gap between letters, as shown. The area of the unshaded portion of the sign, in square units, is

3030

3232

3434

3636

3838

答案:D
知识点:面积分割
难度评级:960
解答:

整个标牌面积为 5×15=755 \times 15 = 75 平方单位。数涂色单位方格可得 H=11H = 11E=11E = 11L=7L = 7P=10P = 10,涂色总面积为 11+11+7+10=3911 + 11 + 7 + 10 = 39

未涂色面积是 7539=3675 - 39 = 36

所以正确答案是 D

The full sign has area 5×15=755 \times 15 = 75 square units. Counting the shaded unit squares in each letter gives H=11,H = 11, E=11,E = 11, L=7,L = 7, and P=10,P = 10, for a shaded total of 11+11+7+10=39.11 + 11 + 7 + 10 = 39.

The unshaded area is 7539=36.75 - 39 = 36.

Thus, the correct answer is D .

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