1988 AMC 8 第 21 题

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21.

在数集 {3,6,9,10}\{3, 6, 9, 10\} 中加入第五个数 nn,使这五个数的平均数等于它们的中位数。nn 的可能取值个数是

A fifth number, n,n, is added to the set of numbers {3,6,9,10}\{3, 6, 9, 10\} to make the mean of the set of five numbers equal to its median. The number of possible values for nn is

11

22

33

44

多于 44

more than 44

答案:C
知识点:平均数中位数(数据)分类讨论
难度评级:1260
解答:

五个数的和是 28+n28 + n,平均数是 28+n5\dfrac{28 + n}{5}。中位数是排序后的中间值,依 nn 的大小可能是 66nn99

如果中位数是 6628+n5=6\dfrac{28 + n}{5} = 6,得 n=2n = 2,确实小于 66。如果中位数是 nn28+n5=n\dfrac{28 + n}{5} = n,得 n=7n = 7,确实在 6699 之间。如果中位数是 9928+n5=9\dfrac{28 + n}{5} = 9,得 n=17n = 17,确实大于 99

每种情况都给出一个有效值,所以 nn 可以是 22771717,共有三个可能值。

所以正确答案是 C

The five numbers have sum 28+n28 + n and mean 28+n5.\dfrac{28 + n}{5}. The median is the middle value when sorted, which is 6,6, n,n, or 99 depending on the size of n.n.

If the median is 66: 28+n5=6\dfrac{28 + n}{5} = 6 gives n=2,n = 2, which is indeed less than 6.6. If the median is nn: 28+n5=n\dfrac{28 + n}{5} = n gives n=7,n = 7, which is between 66 and 9.9. If the median is 99: 28+n5=9\dfrac{28 + n}{5} = 9 gives n=17,n = 17, which is indeed greater than 9.9.

Each case yields a valid value, so nn can be 2,2, 7,7, or 1717 — three possible values.

Thus, the correct answer is C .

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