1986 AMC 8 第 19 题

先试着解答 1986 AMC 8 第 19 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1986 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

19.

旅行开始时,里程表读数为 56,20056{,}200 英里。司机给油箱加满了 66 加仑汽油。旅途中,当里程表读数为 56,56056{,}560 时,司机又给油箱加了 1212 加仑汽油。旅行结束时,司机又加了 2020 加仑汽油;此时里程表读数为 57,06057{,}060。按最接近的十分之一计算,整段旅行中汽车平均每加仑行驶多少英里?
At the beginning of a trip, the mileage odometer read 56,20056{,}200 miles. The driver filled the gas tank with 66 gallons of gasoline. During the trip, the driver filled the tank again with 1212 gallons of gasoline when the odometer read 56,560.56{,}560. At the end of the trip, the driver filled the tank again with 2020 gallons of gasoline; the odometer read 57,060.57{,}060. To the nearest tenth, what was the car’s average miles-per-gallon for the entire trip?
22.522.5
22.622.6
24.024.0
26.926.9
27.527.5
答案:D
知识点:速率
小提示:
旅途中用掉的油只包括出发后补加的油:12+2012 + 20 加仑
The gas used during the trip is only what was added after the start: 12+2012 + 20 gallons
大提示:
用总行驶英里数除以旅途中用掉的加仑数
Divide the total miles driven by the gallons used during the trip
解答:
旅行距离是 57,060−56,200=86057{,}060 - 56{,}200 = 860 英里。最初的 66 加仑只是出发前加满油箱;旅途中真正用掉的是后来为补回油量所加的 12+20=3212 + 20 = 32 加仑。
所以平均值是 86032≈26.9\dfrac{860}{32} \approx 26.9 英里每加仑。
所以正确答案是 D。
The trip was 57,060−56,200=86057{,}060 - 56{,}200 = 860 miles. The initial 66 gallons only topped off the tank before the trip; the gas actually used during the trip is the 12+20=3212 + 20 = 32 gallons later added to replace it.
So the average is 86032≈26.9\dfrac{860}{32} \approx 26.9 miles per gallon.
Thus, the correct answer is D .
LIVE by Po-Shen Loh
LIVE项目

LIVE直播课程

Self-Paced录播课程

启明星Star计划

奖学金项目

关于我们

罗博深是谁?

邮件联系

订阅英文简报

加入我们

申请明星导师

For a more Thought Full world.

© 2026 Expii, Inc.