2026 AMC 8 Problem 21

Attempt Problem 21 of the 2026 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2026 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

21.

Charlotte the spider is walking along a web shaped like a 55-pointed star, shown in the figure below. The web has 55 outer points and 55 inner points. Each time Charlotte reaches a point, she randomly chooses a neighboring point and moves to that point. Charlotte starts at one of the outer points and makes 33 moves (re-visiting points is allowed). What is the probability she is now at one of the outer points of the star?
15\dfrac{1}{5}
14\dfrac{1}{4}
25\dfrac{2}{5}
12\dfrac{1}{2}
35\dfrac{3}{5}
Answer: B
Concepts:random walkbasic probability
Small hint:
Track only outer versus inner points
Big hint:
From an inner point, half of the neighboring points are outer
Video solution:
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Written solution:
From an outer point, Charlotte must move to an inner point. From an inner point, 22 of the 44 neighboring points are outer, so the probability of moving to an outer point is 12\frac{1}{2}. After one move she is inner. After two moves she is outer with probability 12\frac{1}{2} and inner with probability 12\frac{1}{2}. After the third move, only the inner case can move to outer, with probability 12\frac{1}{2}, so the final probability is 12⋅12=14\frac12\cdot\frac12=\frac14.
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