2024 AMC 8 Problem 22

Attempt Problem 22 of the 2024 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2024 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

22.

A roll of tape is 44 inches in diameter and is wrapped around a ring that is 22 inches in diameter. A cross section of the tape is shown in the figure below. The tape is 0.0150.015 inches thick. If the tape is completely unrolled, approximately how long would it be? Round your answer to the nearest 100100 inches.
300300
600600
12001200
15001500
18001800
Answer: B
Concepts:circumferenceestimation
Small hint:
The tape occupies an annulus with outer radius 22 and inner radius 11
Big hint:
Area of tape cross-section equals thickness times total length
Video solution:
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Written solution:
The tape occupies an annulus with outer radius 22 inches and inner radius 11 inch, so its cross-sectional area is π(22−12)=3π. \pi(2^2-1^2)=3\pi.
When unrolled, this same cross section is a rectangle of thickness 0.0150.015 inches and length L.L. Thus 0.015L=3π, 0.015L=3\pi, so L=200π≈628L=200\pi\approx628 inches. Rounded to the nearest 100100 inches, this is 600600 inches.
Thus, B is the correct answer.
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