2022 AMC 8 Problem 19

Attempt Problem 19 of the 2022 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

19.

Mr. Ramos gave a test to his class of 2020 students. The dot plot below shows the distribution of test scores.
Later Mr. Ramos discovered that there was a scoring error on one of the questions. He regraded the tests, awarding some of the students 55 extra points, which increased the median test score to 85.85. What is the minimum number of students who received extra points?
(Note that the median test score equals the average of the 22 scores in the middle if the 2020 test scores are arranged in increasing order.)
22
33
44
55
66
Answer: C
Concepts:median (data)data and graph interpretation
Small hint:
The median is controlled by the 1010th and 1111th scores
Big hint:
Count how many scores are at least 8585 before and after regrading
Solution:
All scores are multiples of 5,5, and adding 55 preserves that fact. If the 1010th and 1111th scores average 8585 but are not both 85,85, then the 1111th score must be at least 90.90. That would require at least 1010 scores of 9090 or more.
However, even after regrading, only the original scores of 8585 or more can reach 90.90. The plot has only 77 such scores, so the two middle scores must both be 85.85.
The plot initially has 77 scores of at least 85.85. To make the 1010th and 1111th scores both 85,85, there must be at least 1111 scores of at least 85.85. Raising four of the 8080’s to 8585 is both necessary and sufficient.
Thus, the correct answer is C.
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