2020 AMC 8 Problem 7

Attempt Problem 7 of the 2020 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2020 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

How many integers between 20202020 and 24002400 have four distinct digits arranged in increasing order? (For example, 23572357 is one such integer.)
99
1010
1515
2121
2828
Answer: C
Concepts:digitscombinations
Small hint:
The first two digits must be 22 and 33
Big hint:
Choose the last two digits from 4,4, 5,5, 6,6, 7,7, 8,8, 99
Video solution:
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Written solution:
The thousands digit must be 2.2. Since the digits are distinct and increasing, the hundreds digit must be 3.3.
The last two digits must be chosen from 4,4, 5,5, 6,6, 7,7, 8,8, 9.9. Once the two digits are chosen, their order is forced.
There are (62)=15\binom{6}{2}=15 such integers.
Thus, the correct answer is C.
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