2019 AMC 8 Problem 7

Attempt Problem 7 of the 2019 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2019 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

Shauna takes five tests, each worth a maximum of 100100 points. Her scores on the first three tests are 76,76, 94,94, and 87.87. In order to average 8181 for all five tests, what is the lowest score she could earn on one of the other two tests?
4848
5252
6666
7070
7474
Answer: A
Concepts:meanoptimization
Small hint:
The five scores must total 5⋅815\cdot81
Big hint:
Make one remaining score as large as possible
Video solution:
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Written solution:
To minimize one of the scores, we have to maximize the other score. Assume that Shauna gets a 100100 on her fourth test.
The sum of the 44 tests is then 76+94+87+100=357. 76 + 94 + 87 + 100 = 357. For an average of 81,81, Shauna’s test scores must add to 5⋅81=405.5 \cdot 81 = 405. This means that she needs to get a 405−357=48405 - 357 = 48 on her last test.
Thus, the correct answer is A.
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