2019 AMC 8 Problem 2

Attempt Problem 2 of the 2019 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2019 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

Three identical rectangles are put together to form rectangle ABCD,ABCD, as shown in the figure below. Given that the length of the shorter side of each of the smaller rectangles is 55 feet, what is the area in square feet of rectangle ABCD?ABCD?
4545
7575
100100
125125
150150
Answer: E
Concepts:rectanglearea
Small hint:
The long side of each small rectangle is two short sides
Big hint:
The big rectangle is 1010 feet by 1515 feet
Video solution:
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Written solution:
From the figure, we can see that the longer side has the same length as two of the shorter sides. This makes it 2⋅5=102 \cdot 5 = 10 feet long.
This tells us that BC=10BC = 10 feet and DC=10+5=15DC = 10 + 5 = 15 feet. Therefore, the area is 10⋅15=15010 \cdot 15 = 150 square feet.
Thus, the correct answer is E.
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