2018 AMC 8 Problem 7

Attempt Problem 7 of the 2018 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

The 55-digit number 2‾\underline{2} 0‾\underline{0} 1‾\underline{1} 8‾\underline{8} U‾\underline{U} is divisible by 9.9. What is the remainder when this number is divided by 8?8?
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Answer: B
Concepts:divisibilitymodular arithmetic
Small hint:
Use the divisibility-by-99 rule to determine UU.
Big hint:
Once UU is known, only the last three digits matter for the remainder modulo 88.
Video solution:
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Written solution:
Notice that a number is divisible by 99 if and only if the sum of its digits is also divisible by 9.9.
The sum of the digits of the 55-digit number in the problem is: 2+0+1+8+U=11+U.2+0+1+8+U= 11+U. As 2‾\underline{2} 0‾\underline{0} 1‾\underline{1} 8‾\underline{8} U‾\underline{U} is divisible by 9,9, 11+U11+U must also be divisible by 9.9. Also, as UU is a digit, we know that 0≤U≤9.0\le U\le 9. This means that UU can only be 7.7.
Now we know that the 55-digit number in question is 20187,20187, and we want to find the remainder when we divide 2018720187 by 8.8. To solve this, simply use long division to see that 20187=2523⋅8+3.20187=2523\cdot 8 + 3. Therefore, the remainder is 3.3.
Thus, the correct answer is B.
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