2018 AMC 8 Problem 25

Attempt Problem 25 of the 2018 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

25.

How many perfect cubes lie between 28+12^8+1 and 218+1,2^{18}+1, inclusive?
4 4
9 9
10 10
57 57
58 58
Answer: E
Concepts:perfect powercounting integers in a range
Small hint:
A perfect cube in the interval has the form n3n^3.
Big hint:
Compare the bounds to 63,73,643,6^3,7^3,64^3, and 65365^3.
Video solution:
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Written solution:
Because 63=216<2576^3=216<257 and 257<343=73257<343=7^3, the smallest cube in the interval is 737^3. Also, 643=218<218+1<65364^3=2^{18}<2^{18}+1<65^3, so the largest cube is 64364^3.
The integer cube roots are therefore 7,8,…,647,8,\ldots,64, a total of 64−7+1=5864-7+1=58.
Thus, E is the correct answer.
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