2015 AMC 8 Problem 7

Attempt Problem 7 of the 2015 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

Each of two boxes contains three chips numbered 1,1, 2,2, 3.3. A chip is drawn randomly from each box and the numbers on the two chips are multiplied. What is the probability that their product is even?
19 \dfrac{1}{9}
29 \dfrac{2}{9}
49 \dfrac{4}{9}
12 \dfrac{1}{2}
59 \dfrac{5}{9}
Answer: E
Concepts:complementary probabilityparity
Small hint:
It may be easier to count the complement: an odd product.
Big hint:
The product is odd only if both drawn chips are odd.
Video solution:
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Written solution:
The product is odd only when both chips are odd. Each box has two odd chips, 11 and 3,3, out of three chips, so the probability of an odd product is (23)2=49.(\dfrac23)^2=\dfrac49.
The probability of an even product is the complement, 1−49=59.1-\dfrac49=\dfrac59.
Thus, E is the correct answer.
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