2015 AMC 8 Problem 20

Attempt Problem 20 of the 2015 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

Ralph went to the store and bought 1212 pairs of socks for a total of $24\$24. Some of the socks he bought cost $1\$1 a pair, some of the socks he bought cost $3\$3 a pair, and some of the socks he bought cost $4\$4 a pair. If he bought at least one pair of each type, how many pairs of $1\$1 socks did Ralph buy?
4 4
5 5
6 6
7 7
8 8
Answer: D
Concepts:system of equationsmodular arithmetic
Small hint:
Let the numbers of $1,\$1, $3,\$3, and $4\$4 pairs be variables.
Big hint:
Subtract the pair-count equation from the cost equation.
Video solution:
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Written solution:
Let a,a, b,b, and cc be the numbers of $1,\$1, $3,\$3, and $4\$4 pairs, respectively. Then a+b+c=12,a+b+c=12, a+3b+4c=24.a+3b+4c=24.
Subtracting gives 2b+3c=12.2b+3c=12. Since at least one pair of each type was bought, b>0b>0 and c>0.c>0. Also 3c<12,3c<12, so c<4.c<4. Modulo 2,2, the equation gives cc even, so c=2.c=2.
Then 2b+6=12,2b+6=12, so b=3,b=3, and a=12−3−2=7.a=12-3-2=7.
Thus, D is the correct answer.
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