2019 AMC 8 Problem 20

Attempt Problem 20 of the 2019 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2019 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

How many different real numbers xx satisfy the equation

(x25)2=16? (x^2 - 5)^2 = 16?

00

11

22

44

88

Answer: D
Concepts:difference of squaresquadratic
Difficulty rating: 1210
Small Hint:

Let x25x^2 - 5 be the quantity being squared

Big Hint:

Solve x25=4x^2 - 5 = 4 and x25=4x^2 - 5 = -4

Video solution:
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Written solution:

Recall that a2b2=(a+b)(ab).a^2 - b^2 = (a + b)(a - b). We can do the following rearrangement. (x25)242=0(x21)(x29)=0 \begin{aligned} (x^2 - 5)^2 - 4^2 &= 0 \\ (x^2 - 1)(x^2 - 9) &= 0 \end{aligned}

From this we can see that there are 44 possible values for x.x.

Thus, the correct answer is D.

Problem 19#19
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