1988 AMC 8 Problem 20

Below is the professionally curated solution for Problem 20 of the 1988 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1988 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:percentage ratio and proportion

Difficulty rating: 930

20.

The glass gauge on a cylindrical coffee maker shows there are $45$ cups left when the coffee maker is $36\%$ full. How many cups of coffee does it hold when it is full?

$80$

$100$

$125$

$130$

$262$

Solution:

Let $n$ be the full capacity. Then $\dfrac{45}{n} = \dfrac{36}{100}.$

Solving, $n = \dfrac{45 \times 100}{36} = 125$ cups.

Thus, the correct answer is C .

← Problem 19#19 Full Exam Problem 21#21 →

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