2014 AMC 8 Problem 16

Attempt Problem 16 of the 2014 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

16.

The “Middle School Eight” basketball conference has 88 teams. Every season, each team plays every other conference team twice (home and away), and each team also plays 44 games against non-conference opponents. What is the total number of games in a season involving the “Middle School Eight” teams?
60 60
88 88
96 96
144 144
160 160
Answer: B
Concepts:basic counting
Small hint:
Count non-conference games separately from conference games.
Big hint:
For conference games, count each team’s home games against the other seven teams.
Solution:
Each team plays 44 non-conference games, for 8⋅4=328\cdot4=32 games involving Middle School Eight teams and non-conference opponents.
Within the conference, each of the 88 teams has 77 home games against the other teams, so there are 8⋅7=568\cdot7=56 conference games. The total is 32+56=8832+56=88.
Thus, B is the correct answer.
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