2014 AMC 8 Problem 17

Below is the professionally curated solution for Problem 17 of the 2014 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 8 solutions, or check the answer key.

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Concepts:distance rate and time

Difficulty rating: 1240

17.

George walks 11 mile to school. He leaves home at the same time each day, walks at a steady speed of 33 miles per hour, and arrives just as school begins.

Today he was distracted by the pleasant weather and walked the first 12\frac{1}{2} mile at a speed of only 22 miles per hour. At how many miles per hour must George run the last 12\frac{1}{2} mile in order to arrive just as school begins today?

4 4

6 6

8 8

10 10

12 12

Solution:

If George normally walks 11 mile at 33 miles per hour, it takes him 13\dfrac{1}{3} hour, or 2020 minutes, to get to school.

Today he walked the first 12\dfrac{1}{2} mile at 22 miles per hour, taking 12÷2=14\dfrac{1}{2}\div2=\dfrac{1}{4} hour, or 1515 minutes. He has 55 minutes, which is 112\dfrac{1}{12} hour, left to cover 12\dfrac{1}{2} mile.

His required speed is 12÷112=6\dfrac{1}{2}\div\dfrac{1}{12}=6 miles per hour.

Thus, B is the correct answer.

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