2010 AMC 8 Problem 2

Attempt Problem 2 of the 2010 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 8 solutions, or check the answer key.

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2.

If ab=a×ba+ba * b = \dfrac{a\times b}{a+b} for a,ba,b positive integers, then what is 510?5 *10?

 310 \ \dfrac{3}{10}

 1 \ 1

 2 \ 2

 103 \ \dfrac{10}{3}

 50 \ 50

Answer: D
Concepts:custom operationfraction
Difficulty rating: 610
Solution:

Given our definition of ab,a*b, we have 510=5×105+10=5015=103.5 *10 = \dfrac{5 \times 10}{5 + 10} = \dfrac{50}{15} = \dfrac{10}{3}.

Thus, the answer is D .

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