2010 AMC 8 Problem 15
Attempt Problem 15 of the 2010 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
15.
A jar contains different colors of gum drops. are blue, are brown, are red, are yellow, and the other gum drops are green. If half of the blue gum drops are replaced by brown gum drops, how many gum drops will be brown?
Answer: C
Small hint:
Use the green count to find the total, then move half the blue count to brown.
Big hint:
Find what percent of the jar is green.
Solution:
Since we have percentages for every color except green, the percent of green is minus the sum of the other colors. This would make the percent of green equal to
Since we know gum drops is we know that the total number of gum drops is
This means there are brown gum drops to start and blue gum drops. If half of the blue gum drops are turned to brown, then more brown gum drops are added. Therefore, we have brown gum drops.
Thus, the answer is C .
Problem 15 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1988 AMC 8
- 1989 AMC 8
- 1990 AMC 8
- 1991 AMC 8
- 1992 AMC 8
- 1993 AMC 8
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