2009 AMC 8 Problem 15

Attempt Problem 15 of the 2009 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

15.

A recipe that makes 55 servings of hot chocolate requires 22 squares of chocolate, 14\dfrac{1}{4} cup sugar, 11 cup water and 44 cups milk. Jordan has 55 squares of chocolate, 22 cups of sugar, lots of water, and 77 cups of milk. If she maintains the same ratio of ingredients, what is the greatest number of servings of hot chocolate she can make?
5185 \dfrac{1}{8}
6146 \dfrac{1}{4}
7127 \dfrac{1}{2}
8348 \dfrac{3}{4}
9789 \dfrac{7}{8}
Answer: D
Concepts:ratio and proportion
Small hint:
Compare how many recipe batches each ingredient can support.
Big hint:
The ingredient that supports the fewest batches limits the servings.
Solution:
We need to find which ingredient is the limiting factor.
Jordan has enough chocolate for 5÷2=525\div2=\dfrac{5}{2} batches, enough sugar for 2÷14=82\div\dfrac{1}{4}=8 batches, and enough milk for 7÷4=747\div4=\dfrac{7}{4} batches.
The milk is limiting, so Jordan can make 5⋅74=354=8345\cdot\dfrac{7}{4}=\dfrac{35}{4}=8\dfrac{3}{4} servings.
Thus, D is the correct answer.
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