2008 AMC 8 Problem 7 — Solution | LIVE by Po-Shen Loh

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2008 AMC 8 Problem 7

Attempt Problem 7 of the 2008 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

If $\dfrac{3}{5}=\dfrac{M}{45}=\dfrac{60}{N},$ what is $M+N?$

$\ 27$

$\ 29$

$\ 45$

$\ 105$

$\ 127$

Answer: E

Concepts:fraction ratio and proportion

Difficulty rating: 820

Solution:

From $\dfrac{3}{5}=\dfrac{M}{45}$ , we get $M=\dfrac{3\cdot45}{5}=27$ .

From $\dfrac{3}{5}=\dfrac{60}{N}$ , we get $3N=300$ , so $N=100$ .

Therefore, $M+N=27+100=127$ .

Thus, E is the correct answer.

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