2007 AMC 8 Problem 7

Attempt Problem 7 of the 2007 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 8 solutions, or check the answer key.

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7.

The average age of 55 people in a room is 3030 years. An 1818-year-old person leaves the room. What is the average age of the four remaining people?

2525

2626

2929

3333

3636

Answer: D
Concepts:mean
Difficulty rating: 900
Solution:

Initially, the total age of everyone in the room is 530=1505 \cdot 30 = 150 years.

After the person leaves, the total age is 15018=132.150 - 18 = 132. With 44 people remaining, the average age becomes 1324=33.\dfrac{132}{4} = 33.

Thus, D is the correct answer.

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