2006 AMC 8 Problem 15

Attempt Problem 15 of the 2006 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

15.

Chandra and Bob, who each have a copy of the book, decide that they can save time by “team reading” the novel. In this scheme, Chandra will read from page 11 to a certain page and Bob will read from the next page through page 760,760, finishing the book. When they are through they will tell each other about the part they read. What is the last page that Chandra should read so that she and Bob spend the same amount of time reading the novel?
425425
444444
456456
484484
506506
Answer: C
Concepts:ratelinear equation
Small hint:
Let xx be the number of pages Chandra reads.
Big hint:
Set Chandra’s time for xx pages equal to Bob’s time for the remaining pages.
Solution:
Let xx be the number of pages that Chandra will read. Then Bob will read 760−x760 - x pages.
For them to read for the same amount of time, 30x=45(760−x)30x=45⋅760−45x75x=45⋅7605x=3⋅760x=3⋅152x=456. \begin{align*} 30x &= 45(760 - x) \\ 30x &= 45 \cdot 760 - 45x \\ 75x &= 45 \cdot 760 \\ 5x &= 3 \cdot 760 \\ x &= 3 \cdot 152 \\ x &= 456. \end{align*}
Thus, C is the correct answer.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.