2004 AMC 8 Problem 22

Attempt Problem 22 of the 2004 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

22.

At a party there are only single women and married men with their wives. The probability that a randomly selected woman is single is 25.\dfrac{2}{5}. What fraction of the people in the room are married men?
13\dfrac{1}{3}
38\dfrac{3}{8}
25\dfrac{2}{5}
512\dfrac{5}{12}
35\dfrac{3}{5}
Answer: B
Concepts:ratio and proportion
Small hint:
Use a convenient number of women matching the ratio 25.\frac{2}{5}.
Big hint:
Married women and married men come in equal numbers.
Solution:
For a convenient ratio model, let there be 55 women in the room. Then there are 5⋅25=25 \cdot \dfrac{2}{5} = 2 single women.
This means that there are 5−2=35 - 2 = 3 married women, which is also the number of married men.
There are a total of 5+3=85 + 3 = 8 people in the room. The fraction of married men is 38.\dfrac{3}{8}.
Thus, B is the correct answer.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.