2003 AMC 8 Problem 7

Attempt Problem 7 of the 2003 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

Blake and Jenny each took four 100100-point tests. Blake averaged 7878 on the four tests. Jenny scored 1010 points higher than Blake on the first test, 1010 points lower than him on the second test, and 2020 points higher on both the third and fourth tests. What is the difference between Jenny’s average and Blake’s average on these four tests?
1010
1515
2020
2525
4040
Answer: A
Concepts:mean
Small hint:
Add Jenny’s four score differences from Blake’s.
Big hint:
Divide the total difference by 44 to compare averages.
Solution:
The total point difference between the two is 10−10+20⋅2=40. 10 - 10 + 20 \cdot 2 = 40. The average of this difference is 40÷4=10.40 \div 4 = 10.
Thus, A is the correct answer.
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