2001 AMC 8 Problem 18

Attempt Problem 18 of the 2001 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2001 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

Two dice are thrown. What is the probability that the product of the two numbers is a multiple of 5?5?
136\dfrac{1}{36}
118\dfrac{1}{18}
16\dfrac{1}{6}
1136\dfrac{11}{36}
13\dfrac{1}{3}
Answer: D
Concepts:dice (probability)complementary probabilitydivisibility
Small hint:
The product is a multiple of 55 exactly when a die shows 55
Big hint:
It is easier to count no die showing 55
Solution:
The only way for the product to be a multiple of 55 is if at least one of the rolls is 5.5.
We can do complementary counting. The probability that neither rolls is a 55 is 56⋅56=2536. \dfrac{5}{6} \cdot \dfrac{5}{6} = \dfrac{25}{36}.
Therefore, the probability that at least one roll is a 55 is 1−2536=1136. 1 - \dfrac{25}{36} = \dfrac{11}{36}.
Thus, D is the correct answer.
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