1993 AMC 8 Problem 18

Attempt Problem 18 of the 1993 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 8 solutions, or check the answer key.

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18.

The rectangle shown has length AC=32,AC = 32, width AE=20,AE = 20, and BB and FF are midpoints of AC\overline{AC} and AE,\overline{AE}, respectively. The area of the quadrilateral ABDFABDF is

320320

325325

330330

335335

340340

Answer: A
Concepts:area decompositiontriangle area

Difficulty rating: 1090

Solution:

Rectangle ACDEACDE has area 32×20=640.32 \times 20 = 640. Triangle BCDBCD has area 16×202=160,\dfrac{16 \times 20}{2} = 160, and triangle DEFDEF has area 10×322=160.\dfrac{10 \times 32}{2} = 160.

The remaining region ABDFABDF has area 640(160+160)=320.640 - (160 + 160) = 320.

Thus, the correct answer is A .

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