2000 AMC 8 Problem 7
Attempt Problem 7 of the 2000 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
7.
What is the minimum possible product of three different numbers of the set
Answer: B
Small hint:
A negative product needs an odd number of negative factors
Big hint:
Compare using three negatives versus one negative and two positives
Solution:
A negative product comes either from three negative factors or from one negative factor and two positive factors.
With three negative factors, the minimum is With one negative factor, use the most negative number and the two largest positive numbers to get Since the minimum possible product is
Thus, B is the correct answer.
Problem 7 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
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- 1989 AMC 8
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