1999 AMC 8 Problem 2

Attempt Problem 2 of the 1999 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1999 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

What is the degree measure of the smaller angle formed by the hands of a clock at 1010 o’clock?
3030
4545
6060
7575
9090
Answer: C
Concepts:clock
Small hint:
Each hour mark is 30∘30^\circ apart
Big hint:
At 1010 o’clock, the hands are two hour marks apart
Solution:
At 1010 o’clock, we have that the hour hand is at 1010 and the minute hand is at 12.12.
This means that the hands are a 16\frac{1}{6} of the entire circle apart. This is equal to 360∘⋅16=60∘. 360^{\circ} \cdot \dfrac{1}{6} = 60^{\circ}.
Thus, C is the correct answer.
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