1996 AMC 8 Problem 2
Attempt Problem 2 of the 1996 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1996 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
2.
José, Thuy, and Kareem each start with the number José subtracts from the number doubles his answer, and then adds Thuy doubles the number subtracts from her answer, and then adds Kareem subtracts from the number adds to his answer, and then doubles the result. Who gets the largest final answer?
José
Thuy
Kareem
José and Thuy
Thuy and Kareem
Answer: C
Small hint:
Work out each person’s three steps in order, beginning with
Big hint:
The order of the steps matters; notice who doubles last, so the they added also gets doubled
Solution:
Starting from José computes Thuy computes and Kareem computes
Kareem doubles last, so the he adds is doubled too, giving the largest result.
Thus, the correct answer is C .
Problem 2 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1988 AMC 8
- 1989 AMC 8
- 1990 AMC 8
- 1991 AMC 8
- 1992 AMC 8
- 1993 AMC 8
- 1994 AMC 8
- 1995 AMC 8
- 1997 AMC 8
- 1998 AMC 8
- 1999 AMC 8
- 2000 AMC 8
- 2001 AMC 8
- 2002 AMC 8
- 2003 AMC 8
- 2004 AMC 8
- 2005 AMC 8
- 2006 AMC 8
- 2007 AMC 8
- 2008 AMC 8
- 2009 AMC 8
- 2010 AMC 8
- 2011 AMC 8
- 2012 AMC 8
- 2013 AMC 8
- 2014 AMC 8
- 2015 AMC 8
- 2016 AMC 8
- 2017 AMC 8
- 2018 AMC 8
- 2019 AMC 8
- 2020 AMC 8
- 2022 AMC 8
- 2023 AMC 8
- 2024 AMC 8
- 2025 AMC 8
- 2026 AMC 8