1993 AMC 8 Problem 7

Attempt Problem 7 of the 1993 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

33+33+33=3^3 + 3^3 + 3^3 =
343^4
939^3
393^9
27327^3
3273^{27}
Answer: A
Concepts:exponent
Small hint:
Adding three copies of 333^3 is the same as 3×333 \times 3^3
Big hint:
3×33=31+33 \times 3^3 = 3^{1+3}
Solution:
Adding three equal terms, 33+33+33=3×33=34=81.3^3 + 3^3 + 3^3 = 3 \times 3^3 = 3^4 = 81.
Thus, the correct answer is A .
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