1992 AMC 8 Problem 7

Attempt Problem 7 of the 1992 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1992 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

The digit-sum of 998998 is 9+9+8=26.9 + 9 + 8 = 26. How many 33-digit whole numbers, whose digit-sum is 2626, are even?
11
22
33
44
55
Answer: A
Concepts:digitsparity
Small hint:
A digit-sum of 2626 forces the three digits to be very large
Big hint:
The only digits that work are 9,9, 9,9, and 88; list the arrangements and keep the even ones
Solution:
A digit-sum of 2626 with three digits requires the digits 9,9, 9,9, and 8.8. The 33-digit numbers using them are 899,899, 989,989, and 998.998.
Of these, only 998998 is even, so there is exactly 11 such number.
Thus, the correct answer is A .
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