1991 AMC 8 Problem 16

Attempt Problem 16 of the 1991 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1991 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

16.

The 1616 squares on a piece of paper are numbered as shown in the diagram. While lying on a table, the paper is folded in half four times in the following sequence:
(1)(1) fold the top half over the bottom half;
(2)(2) fold the bottom half over the top half;
(3)(3) fold the right half over the left half;
(4)(4) fold the left half over the right half.
Which numbered square is on top after step 4?4?
12345678910111213141516\begin{array}{|c|c|c|c|} \hline 1 & 2 & 3 & 4 \\ \hline 5 & 6 & 7 & 8 \\ \hline 9 & 10 & 11 & 12 \\ \hline 13 & 14 & 15 & 16 \\ \hline \end{array}
11
99
1010
1414
1616
Answer: B
Concepts:paper foldingprocess simulation
Small hint:
After each fold, track which squares end up on the bottom (or top) of the stack
Big hint:
Folds 11 and 22 leave the middle rows; folds 33 and 44 leave the middle columns, and the final left-over-right fold flips square 99 to the top
Solution:
Fold 11 (top over bottom) leaves squares 9–169\text{–}16 on the bottom. Fold 22 (bottom over top) leaves 9–129\text{–}12 on the bottom. Fold 33 (right over left) leaves 99 and 1010 on the bottom.
Fold 44 (left over right) puts 1010 on the bottom and brings 99 to the top.
Thus, the correct answer is B .
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