1986 AMC 8 Problem 19

Attempt Problem 19 of the 1986 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1986 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

19.

At the beginning of a trip, the mileage odometer read 56,20056{,}200 miles. The driver filled the gas tank with 66 gallons of gasoline. During the trip, the driver filled the tank again with 1212 gallons of gasoline when the odometer read 56,560.56{,}560. At the end of the trip, the driver filled the tank again with 2020 gallons of gasoline; the odometer read 57,060.57{,}060. To the nearest tenth, what was the car’s average miles-per-gallon for the entire trip?
22.522.5
22.622.6
24.024.0
26.926.9
27.527.5
Answer: D
Concepts:rate
Small hint:
The gas used during the trip is only what was added after the start: 12+2012 + 20 gallons
Big hint:
Divide the total miles driven by the gallons used during the trip
Solution:
The trip was 57,060−56,200=86057{,}060 - 56{,}200 = 860 miles. The initial 66 gallons only topped off the tank before the trip; the gas actually used during the trip is the 12+20=3212 + 20 = 32 gallons later added to replace it.
So the average is 86032≈26.9\dfrac{860}{32} \approx 26.9 miles per gallon.
Thus, the correct answer is D .
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