2021 AMC 12B Fall Problem 6

Attempt Problem 6 of the 2021 AMC 12B Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12B Fall solutions, or check the answer key.

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6.

The greatest prime number that is a divisor of 16,38416{,}384 is 22 because 16,384=214.16{,}384 = 2^{14}. What is the sum of the digits of the greatest prime number that is a divisor of 16,383?16{,}383?
33
77
1010
1616
2222
Answer: C
Concepts:difference of squaresprime factorization
Small hint:
16,383=214−116{,}383 = 2^{14} - 1
Big hint:
Factor as (27−1)(27+1)(2^{7} - 1)(2^{7} + 1)
Solution:
We have 16,383=214−116{,}383 = 2^{14} - 1 =(27−1)(27+1)= (2^{7} - 1)(2^{7} + 1) =127⋅129.= 127 \cdot 129. Then 129=3⋅43,129 = 3 \cdot 43, so 16,383=3⋅43⋅127.16{,}383 = 3 \cdot 43 \cdot 127.
The greatest prime factor is 127,127, whose digit sum is 1+2+7=10.1 + 2 + 7 = 10.
Thus, the correct answer is C.
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