2021 AMC 12B Fall Problem 4 — Solution | LIVE by Po-Shen Loh

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2021 AMC 12B Fall Problem 4

Attempt Problem 4 of the 2021 AMC 12B Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12B Fall solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

Let $n = 8^{2022}.$ Which of the following is equal to $\dfrac{n}{4}?$

$4^{1010}$

$2^{2022}$

$8^{2018}$

$4^{3031}$

$4^{3032}$

Answer: E

Concepts:exponent

Difficulty rating: 1150

Solution:

Write $n = 8^{2022} = 2^{6066}.$ Then $\dfrac{n}{4} = \dfrac{2^{6066}}{2^{2}} = 2^{6064}.$

Since $2^{6064} = 4^{3032},$ this matches the last option.

Thus, the correct answer is E.

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