2021 AMC 12A Fall Problem 4

Attempt Problem 4 of the 2021 AMC 12A Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12A Fall solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

The six-digit number 2‾ 0‾ 2‾ 1‾ 0‾ A‾\underline{2}\,\underline{0}\,\underline{2}\,\underline{1}\,\underline{0}\,\underline{A} is prime for only one digit A.A. What is A?A?
11
33
55
77
99
Answer: E
Concepts:primedivisibility
Small hint:
The number is 202100+A;202100 + A; even AA makes it even, and A=5A = 5 makes it a multiple of 55
Big hint:
For A=1A = 1 and A=7A = 7 the digit sum is a multiple of 3,3, and 202103=11⋅18373202103 = 11 \cdot 18373
Solution:
The number is 202100+A.202100 + A. Any even AA makes it even, and A=5A = 5 makes it divisible by 5,5, so AA must be odd and not 5.5.
For A=1A = 1 the digit sum is 66 (divisible by 33); for A=7A = 7 the digit sum is 1212 (divisible by 33); and 202103=11⋅18373.202103 = 11 \cdot 18373. Only 202109202109 survives all tests, and it is prime.
Thus, the correct answer is E.
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