2021 AMC 12A Fall Problem 10

Attempt Problem 10 of the 2021 AMC 12A Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12A Fall solutions, or check the answer key.

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10.

The base-nine representation of the number NN is 27,006,000,0529.27{,}006{,}000{,}052_9. What is the remainder when NN is divided by 5?5?
00
11
22
33
44
Answer: D
Concepts:modular arithmeticnumber base
Small hint:
9≡−1(mod5),9 \equiv -1 \pmod 5, so 9k≡(−1)k(mod5)9^k \equiv (-1)^k \pmod 5
Big hint:
Take the alternating sum of the base-nine digits (from the right)
Solution:
Since 9≡−1(mod5),9 \equiv -1 \pmod 5, each power 9k≡(−1)k,9^k \equiv (-1)^k, so NN is congruent to the alternating sum of its base-nine digits.
The nonzero digits, with their positions from the right, are 22 (position 00), 55 (position 11), 66 (position 66), 77 (position 99), and 22 (position 1010). The alternating sum is 2−5+6−7+2=−22 - 5 + 6 - 7 + 2 = -2 ≡3(mod5).\equiv 3 \pmod 5.
Thus, the correct answer is D.
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