2020 AMC 12B Problem 4

Attempt Problem 4 of the 2020 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2020 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

The acute angles of a right triangle are a∘a^\circ and b∘,b^\circ, where a>ba \gt b and both aa and bb are prime numbers. What is the least possible value of b?b?
22
33
55
77
1111
Answer: D
Concepts:primeangle sum
Small hint:
The acute angles satisfy a+b=90a + b = 90
Big hint:
Try the smallest primes for bb and check whether 90−b90 - b is also prime
Solution:
Since the angles are complementary, a+b=90.a + b = 90. To minimize b,b, try small primes and require 90−b90 - b to be prime as well.
For b=2,3,5,b = 2, 3, 5, the value 90−b=88,87,8590 - b = 88, 87, 85 is not prime. For b=7,b = 7, we get 90−7=83,90 - 7 = 83, which is prime. So the least possible value is b=7.b = 7.
Thus, the correct answer is D.
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