2020 AMC 12B Problem 15

Attempt Problem 15 of the 2020 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2020 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

15.

There are 1010 people standing equally spaced around a circle. Each person knows exactly 33 of the other 99 people: the 22 people standing next to her or him, as well as the person directly across the circle. How many ways are there for the 1010 people to split up into 55 pairs so that the members of each pair know each other?
1111
1212
1313
1414
1515
Answer: C
Concepts:graph theorycasework
Small hint:
Count perfect matchings using edges that are either adjacent (neighbor) pairs or diameters (across)
Big hint:
Organize by how many diameter pairs are used; only 0,1,3,0, 1, 3, or 55 of them can occur
Solution:
Label the people 00 through 9.9. Allowed pairings use neighbor edges (i,i+1)(i, i + 1) or diameter edges (i,i+5).(i, i + 5). Count perfect matchings by the number of diameter edges used.
Using no diameters, the ten people split into adjacent pairs in 22 ways (all “even” edges or all “odd” edges). Using exactly one diameter, choose it in 55 ways; the remaining two arcs of four people each pair up uniquely, giving 5.5. Using all five diameters gives 11 matching.
If at least one diameter is used, following the forced adjacent pairings around the circle shows that the number of diameters must be odd. With exactly three diameters, the four remaining people must be two opposite adjacent pairs. The position of one such opposite pair determines the matching, giving 55 possibilities. Hence the total is 2+5+5+1=13.2+5+5+1=13.
Thus, the correct answer is C.
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