1972 AMC 12 Problem 15

Attempt Problem 15 of the 1972 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1972 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

15.

A contractor estimated that one of his two bricklayers would take 99 hours to build a certain wall and the other 1010 hours. However, he knew from experience that when they worked together, their combined output fell by 1010 bricks per hour. Being in a hurry, he put both men on the job and found that it took exactly 55 hours to build the wall. The number of bricks in the wall was:

500500

550550

900900

950950

960960

Answer: C
Concepts:ratelinear equation
Difficulty rating: 1790
Small Hint:

Let NN be the number of bricks in the wall

Big Hint:

Their actual combined hourly rate is N9+N1010\frac{N}{9}+\frac{N}{10}-10

Solution:

If the wall contains NN bricks, the individual rates are N9\frac{N}{9} and N10.\frac{N}{10}. Thus 5(N9+N1010)=N. 5\left(\frac N9+\frac N{10}-10\right)=N. Multiplying by 1818 and simplifying gives 19N900=18N,19N-900=18N, hence N=900.N=900.

Therefore, the correct answer is C.

← Problem 14#14
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