2018 AMC 12B Problem 4

Attempt Problem 4 of the 2018 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

A circle has a chord of length 10,10, and the distance from the center of the circle to the chord is 5.5. What is the area of the circle?
25π25\pi
50π50\pi
75π75\pi
100π100\pi
125π125\pi
Answer: B
Concepts:chordPythagorean Theoremcircle area
Small hint:
The radius, half the chord, and the distance to the chord form a right triangle
Big hint:
With legs 55 and 5,5, the radius satisfies r2=52+52r^2=5^2+5^2
Solution:
Dropping a perpendicular from the center to the chord bisects it, forming a right triangle with legs 55 (half the chord) and 55 (the distance), and hypotenuse r.r.
Then r2=52+52=50,r^2=5^2+5^2=50, so the area is πr2=50π.\pi r^2=50\pi.
Thus, the correct answer is B.
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