2017 AMC 12B Problem 9

Attempt Problem 9 of the 2017 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

A circle has center (−10,−4)(-10, -4) and radius 13.13. Another circle has center (3,9)(3, 9) and radius 65.\sqrt{65}. The line passing through the two points of intersection of the two circles has equation x+y=c.x + y = c. What is c?c?
33
333\sqrt{3}
424\sqrt{2}
66
132\dfrac{13}{2}
Answer: A
Concepts:radical axiscirclecoordinate geometry
Small hint:
Write both circles as (x+10)2+(y+4)2=169(x+10)^2 + (y+4)^2 = 169 and (x−3)2+(y−9)2=65(x-3)^2 + (y-9)^2 = 65
Big hint:
Subtract one expanded equation from the other; the quadratic terms cancel
Solution:
The circles are (x+10)2+(y+4)2=169(x+10)^2 + (y+4)^2 = 169 and (x−3)2+(y−9)2=65.(x-3)^2 + (y-9)^2 = 65. Expanding and subtracting the second from the first cancels the x2x^2 and y2y^2 terms and simplifies to x+y=3.x + y = 3. Any intersection point satisfies this, so it is the line through both, and c=3.c = 3.
Thus, the correct answer is A.
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