2017 AMC 12A Problem 20

Attempt Problem 20 of the 2017 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 12A solutions, or check the answer key.

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20.

How many ordered pairs (a,b)(a,b) such that aa is a positive real number and bb is an integer between 22 and 200,200, inclusive, satisfy the equation (logba)2017=logb(a2017)?(\log_b a)^{2017}=\log_b(a^{2017})?

198198

199199

398398

399399

597597

Answer: E
Concepts:logarithmbasic counting
Difficulty rating: 2110
Solution:

Let u=logba.u=\log_b a. Since logb(a2017)=2017logba,\log_b(a^{2017})=2017\log_b a, the equation is u2017=2017u,u^{2017}=2017u, so u=0u=0 or u2016=2017.u^{2016}=2017.

If u=0,u=0, then a=1,a=1, valid for every one of the 199199 bases. If u2016=2017,u^{2016}=2017, then u=±20171/2016,u=\pm2017^{1/2016}, giving 22 values of aa for each base, i.e. 2199=3982\cdot199=398 pairs.

In total there are 199+398=597199+398=597 ordered pairs.

Thus, the correct answer is E.

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