2017 AMC 12A Problem 20

Attempt Problem 20 of the 2017 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 12A solutions, or check the answer key.

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20.

How many ordered pairs (a,b)(a,b) such that aa is a positive real number and bb is an integer between 22 and 200,200, inclusive, satisfy the equation (log⁡ba)2017=log⁡b(a2017)?(\log_b a)^{2017}=\log_b(a^{2017})?
198198
199199
398398
399399
597597
Answer: E
Concepts:logarithmbasic counting
Small hint:
Let u=log⁡ba;u=\log_b a; the equation becomes u2017=2017uu^{2017}=2017u
Big hint:
Either u=0u=0 or u2016=2017;u^{2016}=2017; count the aa values for each of the 199199 allowed bases
Solution:
Let u=log⁡ba.u=\log_b a. Since log⁡b(a2017)=2017log⁡ba,\log_b(a^{2017})=2017\log_b a, the equation is u2017=2017u,u^{2017}=2017u, so u=0u=0 or u2016=2017.u^{2016}=2017.
If u=0,u=0, then a=1,a=1, valid for every one of the 199199 bases. If u2016=2017,u^{2016}=2017, then u=±201712016,u=\pm2017^{\frac{1}{2016}}, giving 22 values of aa for each base, i.e. 2⋅199=3982\cdot199=398 pairs.
In total there are 199+398=597199+398=597 ordered pairs.
Thus, the correct answer is E.
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