2024 AMC 12A Problem 20

Below is the professionally curated solution for Problem 20 of the 2024 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2024 AMC 12A solutions, or check the answer key.

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Concepts:geometric probabilityarea ratio

Difficulty rating: 2100

20.

Points PP and QQ are chosen uniformly and independently at random on sides AB\overline{AB} and AC,\overline{AC}, respectively, of equilateral triangle ABC.\triangle ABC. Which of the following intervals contains the probability that the area of APQ\triangle APQ is less than half the area of ABC?\triangle ABC?

[38,12]\left[\tfrac38,\tfrac12\right]

(12,23]\left(\tfrac12,\tfrac23\right]

(23,34]\left(\tfrac23,\tfrac34\right]

(34,78]\left(\tfrac34,\tfrac78\right]

(78,1]\left(\tfrac78,1\right]

Solution:

With x=APABx=\tfrac{AP}{AB} and y=AQACy=\tfrac{AQ}{AC} uniform on [0,1],[0,1], the area ratio [APQ][ABC]=xy.\tfrac{[APQ]}{[ABC]}=xy. The complementary event xy12xy\ge\tfrac12 requires x12x\ge\tfrac12 and y[12x,1],y\in[\tfrac{1}{2x},1], with probability 1/21(112x)dx=12ln220.153. \int_{1/2}^{1}\left(1-\frac{1}{2x}\right)dx=\frac12-\frac{\ln2}{2}\approx0.153. Therefore P(xy<12)10.153=0.847,P(xy\lt\tfrac12)\approx1-0.153=0.847, which lies in (34,78].\left(\tfrac34,\tfrac78\right]. Thus, the correct answer is D.

Problem 20 in Other Years